With uniform acceleration of movement, the speed of the elevator in 2 s increases from 0.5 m / s to 3.5

With uniform acceleration of movement, the speed of the elevator in 2 s increases from 0.5 m / s to 3.5, then the speed does not change for 4 s. Which way did the elevator go ha all the time.

Data: uniformly accelerated motion (t1 (time) = 2 s; V1.1 (initial speed) = 0.5 m / s; V1.2 (final speed) = 3.5 m / s); uniform movement (t2 (time) = 4 s; V2 (constant speed) = V1.2 = 3.5 m / s).

The path covered by the elevator for the entire time is determined by the formula: S = S1 + S2 = (V1.1 + V1.2) * t / 2 + V2 * t2.

Let’s perform the calculation: S = (0.5 + 3.5) * 2/2 + 3.5 * 4 = 4 + 14 = 18 m.

Answer: For the entire time of movement, the given elevator has passed 18 m.