With uniform evaporation from one square meter of water surface, 0.2 g of water evaporates

With uniform evaporation from one square meter of water surface, 0.2 g of water evaporates per second. How long will it take for a 6 mm deep puddle to dry?

Data: m1 (mass of evaporated water) = 0.2 g (in SI m1 = 0.2 * 10 ^ -3 kg); t1 (evaporation time) = 1 s; S (puddle surface area) = 1 m2; h (puddle depth) = 6 mm (in SI h = 6 * 10 ^ -3 m).

Constants: ρw (water density in a puddle) = 1000 kg / m3.

1) Puddle volume: V = S * h = 1 * 6 * 10 ^ -3 = 6 * 10 ^ -3 m3.

2) The mass of water in the puddle: m = V * ρw = 6 * 10 ^ -3 * 1000 = 6 kg.

3) Puddle drying time: t = m * t1 / m1 = 6 * 1 / (0.2 * 10 ^ -3) = 30,000 s; 500 min or 8 h 20 min.

Answer: The puddle will dry up in 8 hours and 20 minutes.