With uniform movement, the point travels a path of 20 m in 5 s.

With uniform movement, the point travels a path of 20 m in 5 s. Then it continues to move at an accelerated rate and in a time of 3 s travels a path of 21 m. Acceleration?

Given: uniform movement (t1 (time) = 5 s; S1 (distance traveled) = 20 m); accelerated movement (t2 (time) = 3 s; S2 (distance covered) = 21 m).

1) Determine the speed in the first section (initial speed in the second section): V1 = S1 / t1 = 20/5 = 4 m / s.

2) Determine the acceleration in the second section: S2 = V0 * t2 + a * t2 ^ 2/2, whence a * t2 ^ 2/2 = S2 – V0 * t2 and a = 2 * (S2 – V0 * t2) / t2 ^ 2 = 2 * (21 – 4 * 3) / 3 ^ 2 = 2 m / s2.

Answer: The acceleration in the second section was 2 m / s2.