With uniformly accelerated motion in the fourth second, the body travels 2.7m.

With uniformly accelerated motion in the fourth second, the body travels 2.7m. Determine the movement of the body in the seventh second. The initial speed of the body is 2m / s

Data: S4 (distance traveled in the 4th second) = 2.7 m; V0 (initial speed) = 2 m / s.

1) Acceleration of the body: S4 = S4 – S3 = V0 * t4 + 0.5 * a * t4 ^ 2 – V0 * t3 – 0.5 * a * t3 ^ 2 = (V0 * t4 – V0 * t3) + a * (0.5 * t4 ^ 2 – 0.5 * t3 ^ 2) and a = (S4 – (V0 * t4 – V0 * t3)) / (0.5 * t4 ^ 2 – 0.5 * t3 ^ 2) = (2.7 – (2 * 4 – 2 * 3)) / (0.5 * 42 – 0.5 * 3 ^ 2) = 0.2 m / s2.

2) Moving in the 7th second: S7 = S7 – S6 = V0 * t7 + 0.5 * a * t7 ^ 2 – V0 * t6 – 0.5 * a * t6 ^ 2 = 2 * 7 + 0.5 * 0.2 * 7 ^ 2 – 2 * 6 – 0.5 * 0.2 * 6 ^ 2 = 3.3 m.