With what acceleration did the train move on a certain section of the track, if in 12 seconds

With what acceleration did the train move on a certain section of the track, if in 12 seconds its speed increased by 6 m / s?

Initial data: t (duration of movement of a given train) = 12 s; ΔV (change (increase) in train speed) = 6 m / s.

The acceleration of a given train on a certain section of the track is calculated by the formula: a = ΔV / t.

Let’s calculate: a = 6/12 = 0.5 m / s2.

Answer: On a certain section of the track, the acceleration of a given train was 0.5 m / s2.



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