With what acceleration does a particle with a mass of 0.1 g and a charge of 4 μC

With what acceleration does a particle with a mass of 0.1 g and a charge of 4 μC move in a uniform electric field with an intensity of 1000 V / m?

Initial data: m (particle mass) = 0.1 g (0.1 * 10-3 kg); q (particle charge) = 4 μC (4 * 10-6 C); E (strength of a uniform electric field) = 1000 V / m.

The acceleration with which the particle will move is determined using Newton’s second law: F = q * E = m * a, whence a = q * E / m.

Calculation: a = 4 * 10-6 * 1000 / (0.1 * 10-3) = 40 m / s2.

Answer: In a uniform magnetic field, the particle under consideration moves with an acceleration of 40 m / s2.