With what acceleration does a tram moving away move if it picks up speed of 36 km / h in 25 seconds?

Initial data: the tram started moving from a place and V0 (initial speed of the tram) = 0 m / s; V (the speed that the tram gained) = 36 km / h; t (duration of acceleration of the tram) = 25 s.

SI: V = 36 km / h = 10 m / s.

Since the tram started moving at V0 = 0 m / s, the formula for calculating the speed is: V = a * t and a = V / t.

Let’s make a calculation: a = 10/25 = 0.4 m / s2.

Answer: To gain a speed of 36 km / h in 25 s, the tram had to move with an acceleration of 0.4 m / s2.



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