With what acceleration does an electron move in a field with a strength of 10 kv / m?

To find the acceleration of the electron under consideration, we will use Newton’s second law: me * a = qе * E, whence a = qе * E / me.

Variables and constants: qе – electron charge (qе = -1.6 * 10 ^ -19 C); E – field strength (E = 10 kV / m = 10 * 10 ^ 3 V / m); me is the mass of an electron (me = 9.11 * 10 ^ -31 kg).

Let’s make a calculation: a = a = qе * E / me = 1.6 * 10 ^ -19 * 10 * 10 ^ 3 / 9.11 * 10 ^ -31 = 1.756 * 10 ^ 15 m / s2.

Answer: The electron in question should have moved in a field with an acceleration of 1.756 * 10 ^ 15 m / s2.