With what acceleration does the locomotive move in order to increase the congestion from 36

With what acceleration does the locomotive move in order to increase the congestion from 36 / to 54 km / h on the 250m path?

Initial data: S (the path traveled by the locomotive) = 250 m; V1 (speed of the locomotive before acceleration) = 36 km / h; V2 (speed of the locomotive after acceleration) = 54 km / h.

SI system: V1 = 36 km / h = 36 * 1000/3600 m / s = 10 m / s; V2 = 54 km / h = 54 * 1000/3600 m / s = 15 m / s.

The acceleration of the locomotive is expressed from the following formula:

S = (V2 ^ 2 – V1 ^ 2) / 2a; a = (V2 ^ 2 – V1 ^ 2) / 2S.

Let’s do the calculation:

a = (15 ^ 2 – 10 ^ 2) / (2 * 250) = 125/500 = 0.25 m / s ^ 2.

Answer: The locomotive must move with an acceleration of 0.25 m / s ^ 2.