With what acceleration does the tram move when braking if the coefficient of friction is 0.4?
September 23, 2021 | education
| To determine the acceleration of the tram under consideration, we will use Newton’s second law: m * a = Ftr = μ * m * g, whence we express: a = μ * g.
Constants and variables: μ – coefficient of friction (μ = 0.4); g – acceleration due to gravity (g ≈ 10 m / s2).
Calculation: a = μ * g = 0.4 * 10 = 4 m / s2.
Answer: When braking, the given tram moved with an acceleration of 4 m / s2.
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