With what acceleration does the tram move when braking if the coefficient of friction is 0.4?

To determine the acceleration of the tram under consideration, we will use Newton’s second law: m * a = Ftr = μ * m * g, whence we express: a = μ * g.

Constants and variables: μ – coefficient of friction (μ = 0.4); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: a = μ * g = 0.4 * 10 = 4 m / s2.

Answer: When braking, the given tram moved with an acceleration of 4 m / s2.

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