With what acceleration on the rope a load weighing 500 kg is lifted if the tension force F = 15kH acts on it.

According to Newton’s second law:
Fn = ma, where Fn is the pulling force of the cable (Fn = 15 kN = 15 * 10 ^ 3 N), m is the mass of the load (m = 500 kg), and is the acceleration of the load (m / s ^ 2).
Let’s express and calculate the acceleration of the load:
a = Fн / m = (15 * 10 ^ 3) / 500 = 30 m / s ^ 2.
Answer. The acceleration of the load is 30 m / s ^ 2.