With what force a load weighing 100 kg presses on the bottom of the mine cage if the cage; moving evenly?

With what force a load weighing 100 kg presses on the bottom of the mine cage if the cage; moving evenly? If the cage is lowered downward with an acceleration of 0.2 / s2?

Load pressure on the bottom of the mine cage when it moves uniformly:

Р = Fт = mg, where m is the mass of the load (m = 100 kg), g is the acceleration of gravity (we take g = 10 m / s²).

P = mg = 100 * 10 = 1000 N.

Load pressure on the bottom of the mine cage when it goes down with acceleration a = 0.2 m / s2:

P = Ft – ma = mg – ma = 100 * 10 – 100 * 0.2 = 1000 – 20 = 980 N.

Answer: The pressure force of the load is 1000 N and 980 N, respectively.