With what force a uniform electric field acts, the strength of which is 200N / C on an electric charge of 5 * 10 ^ -5 C.

Knowing that by condition it is given that the strength is E = 200 N / C and the charge is 5 * 10 ^ -5 C, and also having the formula E = F / q, we derive from it the force F = Eq
So F = 200N / Kl * 5 * 10 ^ -5Kl = 0.01 N
Answer: F = 0.01H



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