With what force a uniform magnetic field with an induction of 2.5 T acts on a conductor 50 cm long located

With what force a uniform magnetic field with an induction of 2.5 T acts on a conductor 50 cm long located at an angle of 90 ° to the induction vector at a current strength in the conductor of 2 A.

B = 2.5 T.

L = 50cm = 0.5m.

I = 2 A.

∠α = 90 °.

Fump -?

The force with which the magnetic field acts on a conductor with current is called the Ampere force Famp and is determined by the formula: Famp = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction, L is the active length of the conductor, ∠ α is the angle between the direction of the current and the magnetic induction of the field.

Since the conductor is perpendicular to the lines of magnetic induction, then ∠α = 90 °.

Famp = 2 A * 2.5 T * 0.5 m * sin90 ° = 2.5 N.

Answer: an Ampere force Famp = 2.5 N. acts on a conductor in a magnetic field.