With what force do two charges of 1 C each interact at a distance of 1 km from each other?

q1 = 1 Cl.

q2 = 1 Cl.

r = 1 km = 1000 m.

ε0 = 8.85 * 10 ^ -12 Cl ^ 2 / H * m ^ 2.

F -?

According to Coulomb’s law, the force of interaction F between two charges is directly proportional to the charges q1, q2 and inversely proportional to the square of the distance r between them.

The force of interaction F is determined by the formula: F = q1 * q2 / 4 * P * ε0 * r ^ 2, where P is the number pi, ε0 is the electrical constant.

F = 1 C * 1 C / 4 * 3.14 * 8.85 * 10 ^ -12 C ^ 2 / H * m ^ 2 * (1000 m) ^ 2 = 8990 N.

Answer: the interaction force F = 8990 N. appears between the charges.



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