With what force do two protons interact in a vacuum at a distance of 2cm.

Problem data: r (distance between protons) = 2 cm (in SI r = 0.02 m); protons are in a vacuum.

Reference values: q (proton charge) = 1.6 * 10 ^ -19 C; k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

The force of interaction of protons in a vacuum is determined by the formula: F = k * q ^ 2 / r ^ 2.

Let’s make a calculation: F = 9 * 10 ^ 9 * (1.6 * 10-19) ^ 2 / 0.02 ^ 2 = 5.76 * 10 ^ -25 N.

Answer: Protons will interact with a force of 5.76 * 10 ^ -25 N.