With what force does a dog team evenly move a sled with a 250 kg dead weight

With what force does a dog team evenly move a sled with a 250 kg dead weight if the sliding friction coefficient is 0.1?

To determine the force applied by a team of dogs, we apply the equality: m * a = 0 (uniform movement of the sleigh) = F – Ftr and F = Ftr = μ * m * g.

Variables and constants: μ – coefficient of sliding friction (μ = 0.1); m is the mass of the sleigh to be moved (m = 250 kg); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: F = μ * m * g = 0.1 * 250 * 10 = 250 N.

Answer: For even movement of the used sleds, the dog team applies a force of 250 N.