With what force does a magnetic field with an induction of 0.06 T act on a conductor 10 cm long?

With what force does a magnetic field with an induction of 0.06 T act on a conductor 10 cm long? The current strength in the driver is 40A. The lines of induction of the field and the current are mutually perpendicular.

B = 0.06 T.

L = 10 cm = 0.1 m.

I = 40 A.

∠α = 90 °.

Fump -?

A conductor, through which an electric current flows, and which is in a magnetic field, is acted upon by the Ampere Famp force.

Ampere force Famp is determined by the formula: Famp = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction of the field, L is the length of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.

Since the conductor is perpendicular to the lines of force of the magnetic field, then ∠α = 90 °, sin90 ° = 1.

Famp = 40 A * 0.06 T * 0.1 m = 0.24 N.

Answer: Ampere force Famp = 0.24 N. acts on the conductor with current.