With what force does a magnetic field with an induction of 0.06 T act on a conductor 10 cm long?

With what force does a magnetic field with an induction of 0.06 T act on a conductor 10 cm long? The current in the conductor is 40 A. The field induction lines and the current are mutually perpendicular.

B = 0.06 T.

∠α = 90 °.

L = 10 cm = 0.1 m.

I = 40 A.

Fump -?

In a magnetic field, an Ampere force Famp acts on a conductor with a current, the value of which is determined by the formula: Famp = B * I * L * sinα, where B is the magnetic induction of the field, I is the current in the conductor, L is the length of the conductor, which is in the magnetic field, ∠α is the angle between the magnetic induction of the field B and the direction of the current in the conductor.

Since the magnetic induction B with the conductor L are mutually perpendicular, then ∠α = 90 °, sin90 ° = 1.

Famp = 40 A * 0.06 T * 0.1 m = 0.24 N.

Answer: Ampere force Famp = 0.24 N. acts on the conductor.