With what force does a magnetic field with an induction of 10mTl act on a conductor in which the current strength is 50A

With what force does a magnetic field with an induction of 10mTl act on a conductor in which the current strength is 50A, if the length of the active part of the conductor is 0.1 m. The field induction lines and current are mutually perpendicular.

∠α = 90 °.
L = 0.1 m.
B = 10 mT = 0.01 T.
I = 50 A.
∠α = 90 °.
Fump -?
A conductor with a current in a magnetic field is acted upon by the Ampere force Famp: Famp = * B * I * L * sinα, where B is the magnetic induction of the field, I is the current in the conductor L is the length of the active part of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.
The direction of action of the Ampere force is determined by the left hand rule.
∠α = 90 °, sin90 ° = 1.
Famp = 50 A * 0.01 T * 0.1 m = 0.05 N.
Answer: Ampere force Famp = 0.05 N. acts on a conductor with current.