With what force does kerosene press on the bottom of a container with an area of 0.008 and the height of kerosene is 20 cm?

Initial data: S (area of the bottom of the container into which the kerosene is poured) = 0.008 m2; h (height of the column of kerosene in the container) = 20 cm.

Reference data: ρк (kerosene density) = 800 kg / m2; g (acceleration due to gravity) = 9.81 m / s2.

SI system: h = 20 cm = 0.2 m.

1) The volume of kerosene in the tank (cylinder volume): V = S * h = 0.008 * 0.2 = 0.0016 m3.

2) Mass of kerosene in the container: m = ρ * V = 800 * 0.0016 = 1.28 kg.

3) The force of pressure of the mass of kerosene on the bottom of the tank: F = m * g = 1.28 * 9.81 ≈ 12.6 N.



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