With what force does the air press on the surface of a table measuring 12 * 20 cm2

With what force does the air press on the surface of a table measuring 12 * 20 cm2 if the atmospheric pressure is 750 ml of mercury?

Given:

P = 750 millimeters of mercury – air pressure (atmosphere);

a = 12 centimeters = 0.12 meters – table length;

b = 20 centimeters = 0.2 meters – table width.

It is required to determine F (Newton) – with what force the air presses on the table surface.

Let’s convert pressure units to pascals:

P = 750 mmHg = 750 * 133.322 = 99992 Pascal (the result has been rounded to the nearest whole number).

Find the surface area of ​​the table:

s = a * b = 0.12 * 0.2 = 0.024 square meters.

Then the pressure force will be equal to:

F = P * s;

F = 99992 * 0.024 = 2400 Newton = 2.4 kN.

Answer: air presses on the table surface with a force equal to 2.4 kN.