With what force does the atmosphere press on the floor in a 40 m2 classroom on the day when the air pressure is 750 mm Hg?

S = 40 m2.

P = 750 mm. rt. Art.

F -?

The force F with which the atmosphere presses on the floor of the classroom can be expressed by the product of atmospheric pressure P by the floor area S: F = P * S.

The value of atmospheric pressure P is converted into units of the International SI system.

Pressure P = 1 mm. Hg., Art. corresponds to pressure P = 133.3 Pa, therefore, pressure P = 750 mm. rt. Art. corresponds to pressure P = 99992 Pa.

F = 99992 Pa * 40 m2 = 3999680 N = 4000000 N = 4 * 10 ^ 3 kN.

Answer: a force F = 4 * 10 ^ 3 kN acts on the floor of the class.



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