With what force does the atmospheric air press on the surface of a 16 cm by 20 cm notebook sheet?

At normal atmospheric pressure equal to 760 mm Hg. column or p = 101300 Pa, in order to find the force F with which atmospheric air presses on the surface of the notebook sheet, it is necessary to find the product: F = p ∙ S, where S is the area of ​​this notebook sheet. Let’s find, first, the area of ​​a notebook sheet, knowing its dimensions: 16 cm = 0.16 m and 20 cm = 0.20 m. The sheet has the shape of a rectangle, to find the area of ​​a rectangle, find the product of its measurements: S = 0.16 ∙ 0, 20 = 0.032 (sq. M). Then F = 101300 Pa ∙ 0.032 sq. m = 3241.6 N.
Answer: with a force of 3241.6 N, atmospheric air presses on the surface of the notebook sheet.