With what force does the earth attract a 25-ton train carriage to itself?

Data: m (train car mass) = 25 t (in SI m = 25 * 10 ^ 3 kg); we assume that the distance between the car and the Earth’s surface is approximately equal to zero.

Constants: G (gravitational constant) = 6.67 * 10 ^ -11 m3 / (kg * s2); Rz (average radius of the Earth) = 6371 * 10 ^ 3 m; Mz (mass of the Earth) = 5.9726 * 10 ^ 24 kg.

The force of attraction of the train carriage: F = G * (m * Mz) / Rz2.

Calculation: F = 6.67 * 10 ^ -11 * (25 * 10 ^ 3 * 5.9726 * 1024) / (6371 * 10 ^ 3) ^ 2 = 245 366 N ≈ 245 kN.

Answer: The earth attracts the train car with a force of 245 kN.