With what force does the oil press on the bottom of the tank, the area of which is 50m squared if the depth of the tank is 6 m?
The pressure force formula is as follows – p = F / S, where p is the pressure (unit of measurement – Pa (pascal) or N / m²), F is the force pressing on a certain area – in our case it is the weight of the oil “column” in tank (unit of measurement – N (newton), S – area,
to which this force is applied (m²).
The weight of oil will be determined by the formula p = ρVg, where V is the volume, ρ is the specific gravity (of oil), g is the acceleration of gravity.
Substituting one formula into another and making simple reductions, we obtain the final formula for the pressure of the liquid (oil) column – p = ρgh, where h is the height of the liquid column (in our case, the depth of the tank). Substituting the values we have, we get – 850 kg / m³ * 9.8 m / s² * 6 m = 49.98 kN (the most common value for the specific gravity of oil is most often 820-900 kg / m³, we took the average value).
Thus, the force of pressure on the bottom of the tank will be 49.98 kN / m² or 49.98 kPa.
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