With what force does the oil press on the bottom of the tank, the area of which is 50m

With what force does the oil press on the bottom of the tank, the area of which is 50m squared if the depth of the tank is 6 m?

The pressure force formula is as follows – p = F / S, where p is the pressure (unit of measurement – Pa (pascal) or N / m²), F is the force pressing on a certain area – in our case it is the weight of the oil “column” in tank (unit of measurement – N (newton), S – area,
to which this force is applied (m²).

The weight of oil will be determined by the formula p = ρVg, where V is the volume, ρ is the specific gravity (of oil), g is the acceleration of gravity.

Substituting one formula into another and making simple reductions, we obtain the final formula for the pressure of the liquid (oil) column – p = ρgh, where h is the height of the liquid column (in our case, the depth of the tank). Substituting the values ​​we have, we get – 850 kg / m³ * 9.8 m / s² * 6 m = 49.98 kN (the most common value for the specific gravity of oil is most often 820-900 kg / m³, we took the average value).

Thus, the force of pressure on the bottom of the tank will be 49.98 kN / m² or 49.98 kPa.

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