With what force is a piece of glass with a volume of 10 cm3 pushed out by kerosene?

Let’s translate all the values from given to the SI system:
V = 10 cm³ = 10 * 10 ^ -6 m³.
A buoyant force equal to the weight of the displaced fluid acts on a body immersed in a liquid, and is called the Archimedes force:
Fа = ρж * g * V, where ρж is the density of the liquid, g is the acceleration of gravity of a body raised above the Earth g = 9.8 m / s², V is the volume of the body.
According to the reference book, the density of kerosene is ρzh = 800 kg / m³.
Substitute the numerical values, find the pressure:
Fa = ρl * g * V = 800 * 9.8 * 10 * 10 ^ -6 = 0.0784 N.
Answer: the buoyancy force is 0.0784 N.