With what force is a piece of wood weighing 800 g pushed out when it is completely immersed in water?

With what force is a piece of wood weighing 800 g pushed out when it is completely immersed in water? The density of the tree is p = 0.5 g / cm3. Density of water p = 1.0 g / cm3

To calculate the pushing force of a piece of wood with full immersion in water, we will use the formula: Fa = ρw * g * V = ρw * g * m / ρd.

Values of variables and constants: ρw – water density (ρw = 1 g / cm3 = 1000 kg / m3); g – acceleration due to gravity (g ≈ 10 m / s2); m is the mass of a piece of wood (m = 800 g = 0.8 kg); ρd – wood density (ρd = 0.5 g / cm3 = 500 kg / m3).

Let’s perform the calculation: Fa = ρw * g * m / ρd = 1000 * 10 * 0.8 / 500 = 16 N.

Answer: A piece of wood is pushed out of the water with a force of 16 N.