With what force is it necessary to act on the piston of a hydraulic press with

With what force is it necessary to act on the piston of a hydraulic press with an area of 10 cm² so that 2 kN acts on the piston with an area of 400 cm²?

Since the fluid pressure in the pistons of a hydraulic press is the same, the ratio F1 / S1 = F2 / S2 will be valid.
Hence: F1 = S1 * F2 / S2, where F1 is the pressure force on the first piston, S1 is the surface area of the first piston (S1 = 10 cm ^ 2 = 10 * 10 ^ -4 m ^ 2), F2 is the pressure force on the second piston (F2 = 2 kN = 2 * 10 ^ 3 N), S2 is the surface area of the second piston (S2 = 400 cm ^ 2 = 400 * 10 ^ -4 m ^ 2).
F1 = S1 * F2 / S2 = ((10 * 10 ^ -4) * 2 * 10 ^ 3) / (400 * 10 ^ -4 m ^ 2) = 2 / 0.04 = 50 N
Answer. You need a pressure force of 50 N.