With what force is the spring stretched to which a brass bar of 10 x 8 x 5cm was suspended?

Data: a (length of a brass bar) = 10 cm; b (bar width) = 8 cm; s (bar thickness) = 5 cm.

Constants: g (acceleration of gravity) = 9.81 m / s2; by condition ρl (density of brass) = 8500 kg / m3.

SI: a = 10 cm = 0.1 m; b = 8 cm = 0.08 m; s = 5 cm = 0.05 m.

1) Calculate the volume of the brass bar: V = a * b * s = 0.1 * 0.08 * 0.05 = 0.0004 m3.

2) Determine the mass of the bar: m = ρ * V = 8500 * 0.0004 = 3.4 kg.

3) The force with which the bar stretches the spring: F = m * g = 3.4 * 9.81 = 33.354 N.