With what force it is necessary to hold the handle of the winch so that the load weighing 15 kg

With what force it is necessary to hold the handle of the winch so that the load weighing 15 kg in the gravity field of the Earth remains stationary. Winch radius 0.5m, handle length 1m. The weight of the winch is neglected.

m = 15 kg.

g = 10 m / s2.

r = 0.5 m.

R = 1 m.

Fr -?

The condition for the balance of the winch is the equality of the moments of the forces of the load and the hand of a person: Mg = Mr.

The moment of force M is called the product of force F and the smallest distance from the line of action of the force to the axis of rotation r: M = r * F.

Mg = r * Fg.

Mр = R * Fр.

The load acts with the force of its weight Fg, the value of which is determined by the formula: Fg = m * g, where m is the mass of the load, g is the acceleration of gravity.

r * m * g = R * Fр.

Fр = r * m * g / R.

Fr = 0.5 m * 15 kg * 10 m / s2 / 1 m = 75 N.

Answer: the handle of the winch must be held with a force of Fр = 75 N.