With what force the air presses on a table 1.5 m long and 80 cm wide. Air pressure is considered normal – 760 mm Hg.

Given:

P = 760 millimeters of mercury = 101325 Pascal – normal atmospheric pressure;

a = 1.5 meters – table length;

b = 80 centimeters = 0.8 meters – table width.

It is required to determine F (Newton) – with what force the air presses on the table surface.

Find the surface area of the table:

S = a * b = 1.5 * 0.8 = 1.2 square meters.

Then the force will be equal to:

F = P * S = 101325 * 1.2 = 121590 Newton = 121.6 kN.

Answer: air presses against the table surface with a force equal to 121.6 kN.