With what force will 2 point charges of 1 C each interact if they are placed in a vacuum

With what force will 2 point charges of 1 C each interact if they are placed in a vacuum at a distance of 1 km from each other

To calculate the required force of interaction of given point charges in vacuum, we will use Coulomb’s law: F = k * q1 * q ^ 2 / r2 = k * q ^ 2 / r ^ 2.

Variables and constants: k – coefficient of proportionality (k = 9 * 10 ^ 9 N * m2 / Kl2); q is the charge of each of the point charges (q = 1 C); r is the distance between charges (r = 1 km = 1 * 10 ^ 3 m).

Let’s perform the calculation: F = k * q ^ 2 / r ^ 2 = 9 * 10 ^ 9 * 12 / (1 * 10 ^ 3) ^ 2 = 9 * 10 ^ 3 H = 9 kN.

Answer: The force of interaction is 9 kN.