With what force will the electric field act on the ball, the charge of which is 2 nC

With what force will the electric field act on the ball, the charge of which is 2 nC, if it is located at a distance of 2 m from the body with a charge of 4 μC?

Task data: q1 (ball charge) = 2 nC (2 * 10 ^ -9 C); r (distance between ball and body) = 2 m; q2 (body charge) = 4 μC (4 * 10 ^ -6 C).

Constants: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

To find the force acting on the considered ball from the side of the field, we apply the Coulomb’s law: F = k * q1 * q2 / r ^ 2.

Calculation: F = 9 * 10 ^ 9 * 2 * 10 ^ -9 * 4 * 10 ^ -6 / 2 ^ 2 = 18 * 10 ^ -6 N (18 μN).

Answer: The field acts on the considered ball with a force of 18 μN.



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