With what force will the pilot weighing 75 kg press on the seat when the plane exits the dive at a speed of 540

With what force will the pilot weighing 75 kg press on the seat when the plane exits the dive at a speed of 540 kilometers per hour if the trajectory radius is 450 m.

When solving the problem, we use Newton’s second law: F = ma; F = mV ^ 2/2. Let’s substitute the numbers in the formulation of the law F = 75 * 2916/450 = 486 N.
Answer: F = 486 H



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