With what force will two bodies with a charge of + 15nC and -2pC interact located at a distance of 10 cm

With what force will two bodies with a charge of + 15nC and -2pC interact located at a distance of 10 cm from each other in a vacuum?

According to Coulomb’s law:

F = k * | q1 | * | q2 | / r², k is the proportionality coefficient (k = 9 * 109 N * m² / Kl²), q1 is the charge of the first body (q1 = 15 nC = 15 * 10-9 C), q2 is the charge of the second body (q2 = – 2 pC = -2 * 10-12 C), r is the distance between the bodies (r = 10 cm = 0.1 m).

Let’s calculate the force of interaction:

F = k * | q1 | * | q2 | / r² = 9 * 109 * 15 * 10-9 * 2 * 10-12 / 0.12 = 0.000000027 N = 0.027 * 10-6 N = 0.027 μN.

Answer: Two bodies will interact with a force of 0.027 μN.