With what maximum acceleration can a 500 kg load be lifted vertically upward if the rope can withstand

With what maximum acceleration can a 500 kg load be lifted vertically upward if the rope can withstand a maximum tension of 9kN?

Initial data: m (weight of the load lifted on the rope) = 500 kg; F (maximum stress that the rope can withstand) = 9 kN (9 * 10 ^ 3 N).

Reference data: g (acceleration due to gravity) ≈ 10 m / s.

The maximum acceleration with which it will be possible to lift this load, we express from the formula: F = P = m * (g + a), whence g + a = P / m and a = P / m – g.

Calculation: a = 9 * 10 ^ 3/500 – 10 = 8 m / s2.

Answer: This load can be lifted with a maximum acceleration of 8 m / s2.