With what speed does the ends of the minute and hour hands of the tower clock move if their length of the minute hand is 1.44 m, and the length of the hour hand is 1.2 m?
Data: Lm (length of the minute hand) = 1.44 m; Lh (hour hand length) = 1.2 m.
Constants: Tm (period of the minute hand) = 3600 s; Pt (hour hand period) = 43200 s.
1) Speed of the end of the minute hand: Vm = 2 * Π * R / T = 2 * Π * Lm / Tm = 2 * 3.14 * 1.44 / 3600 = 0.002512 m / s.
2) The speed of the end of the hour hand: Vh = 2 * Π * Lh / Th = 2 * 3.14 * 1.2 / 43200 = 1.744 * 10-4 m / s.
Answer: The ends of the minute and hour hands move at a speed of 0.002512 m / s and 1.744 * 10-4 m / s, respectively.
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