With what speed should a body be thrown down from a height of 40 m so that it reaches

With what speed should a body be thrown down from a height of 40 m so that it reaches the surface of the earth in 1 s?

h = 40 m.

g = 9.8 m / s ^ 2.

t = 1 s.

V0 -?

When moving downward, the body moves with the acceleration of gravity g.

For uniformly accelerated motion, the height of the fall h is determined by the formula: h = V0 * t + g * t ^ 2/2, where V0 is the initial velocity of the body, t is the time of the body falling, g is the acceleration of gravity.

From the formula, we express the initial speed of movement V0.

V0 * t = h – g * t ^ 2/2;

V0 = h / t – g * t / 2.

V0 = 40 m / 1 s – 9.8 m / s ^ 2 * 1 s / 2 = 35.1 m / s.

Answer: the initial velocity of the body should be V0 = 35.1 m / s.