With what speed the cyclist passes the rounding of the cycle track with a radius of 25 m

With what speed the cyclist passes the rounding of the cycle track with a radius of 25 m, if his centripetal acceleration is 4 m / s2.

Task data: R (radius of curvature of the cycle track) = 25 m; an (cyclist’s centripetal acceleration) = 4 m / s2.

We express the speed with which the cyclist under consideration will pass the curves of the cycle track from the formula: an = V ^ 2 / R, whence V = √ (an * R).

Let’s calculate: V = √ (4 * 25) = 10 m / s.

Answer: The cyclist in question passed the rounding of the cycle track at a speed of 10 m / s.