With what speed will a body thrown vertically down from a height of 8 meters and a speed of 4 m / s fall to the ground?
h = 8 m.
V0 = 4 m / s.
g = 9.8 m / s2.
Let us express the height of the stone throw h by the formula: h = (V² – V0²) / 2 * g.
V² – V0² = 2 * g * h.
V² = V0² + 2 * g * h.
V = √ (V0² + 2 * g * h).
V = √ ((4 m / s) 2 + 2 * 9.8 m / s2 * 8 m) = 13 m / s.
Answer: at the moment of impact on the ground, the body has a speed of V = 13 m / s.
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