Within 10 minutes, a charge of 12cl passes through the conductor. What is the current in the conductor?

These tasks: t (duration of the passage of the charge) = 10 min (in SI t = 600 s); q (charge amount) = 12 Cl.

The current strength will be equal to the ratio of the magnitude of the charge to the time of its passage through the taken conductor: I = q / t.

Let’s make a calculation: I = 12/600 = 0.02 A.

Answer: The required current strength is 0.02 A.