Write an infinitely decreasing geometric progression with b1 = 3, S = 7/2.
| March 31, 2021 | education
Let’s use the formula for the sum of an infinitely decreasing geometric progression.
Sn = b1 / (1 – q) = 7/2.
Find the denominator of the progression.
3 / (1 – q) = 7/2.
7 – 7 * q = 6.
q = 1/7.
Then:
b1 = 3.
b2 = 3 * 1/7 = 3/7.
b3 = 3 * (1/7) ^ 2 = 3/49.
bn = 3 * (1/7) ^ n-1.
Answer: bn = 3 * (1/7) ^ n-1.
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