Write down 2 molecular reaction equations corresponding to the abbreviated ionic equation: Al (+3) + OH (-) = Al (OH) 3.

The reaction takes place between substances such as aluminum hydroxide and sulfuric acid. The reaction is neutralized. As a result of this substitution reaction, an aluminum sulfate salt is formed and water is released. In order to equalize the reaction, we need to put 2 in front of aluminum hydroxide, number 3 in front of sulfuric acid, and in the reaction products before water 6. The molecular equation of the reaction can be written as follows:

2 Al (OH) 3 + 3 H2SO4 = Al2 (SO4) 3 + 6 H2O

The ionic reaction equation can be written as follows:

6 Na + + 6 OH – + 2 Al 3+ + 3 SO4 2- = 6 Na + + 3 SO4 2- + 2 Al (OH) 3

The abbreviated ionic equation can be written as follows:

6 OH – + 2 Al 3+ = 2 Al (OH) 3.