Write down the combustion reactions of acetylene, etiquette, ethane and benzene?

Let’s execute the solution:

Let’s write the equations:
2С2Н2 + 5О2 = 4СО2 + 2Н2О + Q – acetylene burns, heat, carbon dioxide, water is released;

С2Н4 + 3О2 = 2СО2 + 2Н2О + Q – ethylene burns with a bright glowing flame;

2С2Н6 + 7О2 = 4СО2 + 6Н2О + Q – ethane combustion process;

2С6Н6 + 9О2 = 12СО2 + 6Н2О + Q – benzene burns with a strong smoky flame.

The processes of combustion of hydrocarbons, which are accompanied by the release of heat, are presented.