Write down the equation of the straight line passing through the points М1 (-2; 5) and М2 (2; 2)

First, we find the canonical equation for a given line:
(x – xM1) / (xM2 – xM1) = (y – yM1) / (yM2 – yM1).
Substitute the coordinate values:
xM1 = -2, xM2 = 2, yM1 = 5, yM2 = 2;
(x – (-2)) / (2 – (-2)) = (y -5) / (2-5);
Answer: (x + 2) / 4 = (y – 5) / – 3.

We pass from the canonical to the general equation of the straight line, multiplying both sides by 12:
3 (x + 2) = -4 (y – 5);
3x + 6 = -4y + 20;
Answer: 3x + 4y – 14 = 0.

Equation of a straight line with a slope:
4y = -3x +14;
Answer: y = – (3/4) x +7/2.