Write down the equations for the reaction of calcium carbide formation when calcium oxide interacts with coal.

Write down the equations for the reaction of calcium carbide formation when calcium oxide interacts with coal. How much calcium oxide is needed to obtain 1 ton of calcium carbide?

Given:
m (CaC2) = 1 t = 1,000,000 g

To find:
m (CaO) -?

Decision:
1) Write the reaction equation:
CaO + 3C => CaC2 + CO;
2) Calculate the molar masses of CaC2 and CaO:
M (CaC2) = Mr (CaC2) = Ar (Ca) * N (Ca) + Ar (C) * N (C) = 40 * 1 + 12 * 2 = 64 g / mol;
M (CaO) = Mr (CaO) = Ar (Ca) * N (Ca) + Ar (O) * N (O) = 40 * 1 + 16 * 1 = 56 g / mol;
3) Calculate the amount of CaC2:
n (CaC2) = m (CaC2) / M (CaC2) = 1,000,000 / 64 = 15,625 mol;
4) Determine the amount of CaO substance:
n (CaO) = n (CaC2) = 15625 mol;
5) Calculate the mass of CaO:
m (CaO) = n (CaO) * M (CaO) = 15625 * 56 = 875000 g.

Answer: The mass of CaO is 875000 g.