Write down the first five terms of the arithmetic progression if An = 12-6n

We know from the condition that the arithmetic progression is given by its general form an = 12 – 6n. In order to write down the first five of its members, we need to alternately substitute the value n from 1 to 5 into the expression and perform calculations.

So, we substitute n = 1 and we get the first term of the arithmetic progression:

a1 = 12 – 6 * 1 = 12 – 6 = 6.

This number is 6.

Now let’s calculate all the others:

a2 = 12 – 6 * 2 = 12 – 12 = 0;

a3 = 12 – 6 * 3 = 12 – 18 = -6;

a4 = 12 – 6 * 4 = 12 – 24 = -12;

a5 = 12 – 6 * 5 = 12 – 30 = -18.