Write down the formula for the hydrocarbon: 3,3-dimethylpentine-1. Write 1 isomer and 1 homologue for this substance.

To solve the problem, let us remember what isomers and homologues are.

According to Butlerov’s teachings, organic compounds that differ in their chemical structure by one CH2 group in the chain are considered homologues. Such substances have similar physical and chemical properties, but different compositions.

Isomers are identical in composition, but differ in chemical structure.

For the substance 3,3-dimethylpentine-1 [1] with the gross formula C7H12, the isomers will be substances with the same gross formula, but the structural formulas will differ. This, for example, 3,4-dimethylpentine-1 or 4-methylhexine-2 [3]

Homologues for 3,3-dimethylpentine-1 are substances, for example, with the gross formula C6H10. This, for example, 3-methyl-3-ethylpentine-1 or 3,3-dimethylhexine-1 [2]



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.