Write down the molecular and ionic equations for the interaction of barium hydroxide solution

Write down the molecular and ionic equations for the interaction of barium hydroxide solution with substances: a) sulfuric acid; b) phosphorus (V) oxide; c) silver nitrate.

Let’s write down the reactions:
a) Ba (OH) 2 + H2SO4 = BaSO4 + 2H2O – ion exchange reaction, obtained barium sulfate in the precipitate;
Ba2 + + 2OH- + 2H + + SO42- = BaSO4 + 2H + + 2OH- – full;
Ba2 + + SO42- = BaSO4 – abbreviated;
b) 3Ba (OH) 2 + P2O5 = Ba3 (PO4) 2 + 3H2O – molecular equation;
3Ba2 + + 6OH- + P2O5 = Ba3 (PO4) 2 + 6H + + 6OH- – ionic;
3Ba + P2O5 = Ba3 (PO4) 2 + 6H + – abbreviated;
c) Ba (OH) 2 + 2AgNO3 = Ba (NO3) 2 + 2Ag (OH) – molecular;
Ba2 + + 2OH- + 2Ag + + 2NO3- = Ba2 + + 2NO3- + 2Ag (OH) – ionic;
2OH- + 2Ag + = 2AgOH – abbreviated.
These ion exchange reactions go to the end, since substances in the precipitate are formed – barium sulfate, barium phosphate, silver hydroxide.